Для поиска файла в каталоге с использованием различных языков программирования можно использовать следующие методы:

1. Python:

   import os
   def search_file(directory, filename):
   for root, dirs, files in os.walk(directory):
       if filename in files:
           return os.path.join(root, filename)
   return None
   # Example usage
   directory = "/path/to/directory"
   filename = "example.txt"
   result = search_file(directory, filename)
   print(result)  # Returns the path of the file if found, otherwise None

2. Java:

   import java.io.File;
   public class FileSearch {
   public static String searchFile(String directory, String filename) {
       File dir = new File(directory);
       File[] files = dir.listFiles();
       if (files != null) {
           for (File file : files) {
               if (file.getName().equals(filename)) {
                   return file.getAbsolutePath();
               }
           }
       }
       return null;
   }
   // Example usage
   public static void main(String[] args) {
       String directory = "/path/to/directory";
       String filename = "example.txt";
       String result = searchFile(directory, filename);
       System.out.println(result);  // Returns the path of the file if found, otherwise null
   }
   }

3. C++:

   #include <iostream>
   #include <filesystem>
   namespace fs = std::filesystem;
   std::string searchFile(const std::string& directory, const std::string& filename) {
   for (const auto& entry : fs::recursive_directory_iterator(directory)) {
       if (entry.is_regular_file() && entry.path().filename() == filename) {
           return entry.path().string();
       }
   }
   return "";
   }
   // Example usage
   int main() {
   std::string directory = "/path/to/directory";
   std::string filename = "example.txt";
   std::string result = searchFile(directory, filename);
   std::cout << result << std::endl;  // Returns the path of the file if found, otherwise an empty string
   return 0;
   }

4. JavaScript (Node.js):

   const fs = require('fs');
   const path = require('path');
   function searchFile(directory, filename) {
   const files = fs.readdirSync(directory);
   for (const file of files) {
       const filePath = path.join(directory, file);
       const stat = fs.statSync(filePath);
       if (stat.isFile() && file === filename) {
           return filePath;
       }
   }
   return null;
   }
   // Example usage
   const directory = '/path/to/directory';
   const filename = 'example.txt';
   const result = searchFile(directory, filename);
   console.log(result);  // Returns the path of the file if found, otherwise null