Использование дельты времени для допуска:

from datetime import datetime, timedelta
def assert_datetime_within_tolerance(dt1, dt2, tolerance):
assert abs(dt1 - dt2) <= tolerance, f"Datetimes not within tolerance: {dt1} and {dt2}"
# Usage example
dt1 = datetime(2022, 1, 1, 12, 0, 0)
dt2 = datetime(2022, 1, 1, 12, 0, 5)
tolerance = timedelta(seconds=10)
assert_datetime_within_tolerance(dt1, dt2, tolerance)

Использование пользовательской функции для допуска:

from datetime import datetime
def assert_datetime_within_tolerance(dt1, dt2, tolerance_seconds):
assert abs(dt1 - dt2).total_seconds() <= tolerance_seconds, f"Datetimes not within tolerance: {dt1} and {dt2}"
# Usage example
dt1 = datetime(2022, 1, 1, 12, 0, 0)
dt2 = datetime(2022, 1, 1, 12, 0, 8)
tolerance_seconds = 10
assert_datetime_within_tolerance(dt1, dt2, tolerance_seconds)

Использование такой библиотеки, как pytestсо встроенными утверждениями допуска по дате и времени:

from datetime import datetime
import pytest
# Usage example
dt1 = datetime(2022, 1, 1, 12, 0, 0)
dt2 = datetime(2022, 1, 1, 12, 0, 12)
tolerance_seconds = 10
pytest.approx(dt1.timestamp(), abs=tolerance_seconds) == dt2.timestamp()